x^2+159x-4800=0

Solution for x^2+159x-4800=0 equation:

x^2+159x-4800=0

a = 1; b = 159; c = -4800;
Δ = b2-4ac
Δ = 1592-4·1·(-4800)
Δ = 44481
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(159)-\sqrt{44481}}{2*1}=\frac{-159-\sqrt{44481}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(159)+\sqrt{44481}}{2*1}=\frac{-159+\sqrt{44481}}{2}
$